If a sewage spill of 166 gallons per minute is ongoing for 22 minutes, how many reportable unrecoverable gallons of raw sewage had reached the creek?

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Multiple Choice

If a sewage spill of 166 gallons per minute is ongoing for 22 minutes, how many reportable unrecoverable gallons of raw sewage had reached the creek?

The main idea is to convert a continuous discharge rate into total volume: Volume = Rate × Time. Here, 166 gallons per minute for 22 minutes gives 166 × 22 = (166 × 20) + (166 × 2) = 3,320 + 332 = 3,652 gallons. So 3,652 gallons of raw sewage reached the creek, which is the reportable unrecoverable amount.

The main idea is to convert a continuous discharge rate into total volume: Volume = Rate × Time. Here, 166 gallons per minute for 22 minutes gives 166 × 22 = (166 × 20) + (166 × 2) = 3,320 + 332 = 3,652 gallons. So 3,652 gallons of raw sewage reached the creek, which is the reportable unrecoverable amount.

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